Solve following using suitable identities : (998)^{3}

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2. Polynomials

easy

Evaluate the following using suitable identities : $(998)^{3}$

A

$988411902$

B

$994011992$

C

$989012392$

D

$994012092$

Solution

We have

$998 =1000-2 $

$\therefore$ $(999)^{3} =(1000-2)^{3}=(1000)^{3}-(2)^{3}-3(1000)(2)[1000-2]$

$=1000000000-8-6000[1000-2]$

$=1000000000-8-6000000-12000$

$=994011992$

Standard 9

Mathematics

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